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97 lines
2.2 KiB
Python
97 lines
2.2 KiB
Python
"""Python 2/3 compat layer leftovers."""
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import decimal as _decimal
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import math as _math
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import warnings
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from contextlib import redirect_stderr, redirect_stdout
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from io import BytesIO
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from io import StringIO as UnicodeIO
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from types import SimpleNamespace
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from .textTools import Tag, bytechr, byteord, bytesjoin, strjoin, tobytes, tostr
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warnings.warn(
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"The py23 module has been deprecated and will be removed in a future release. "
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"Please update your code.",
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DeprecationWarning,
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)
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__all__ = [
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"basestring",
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"bytechr",
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"byteord",
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"BytesIO",
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"bytesjoin",
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"open",
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"Py23Error",
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"range",
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"RecursionError",
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"round",
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"SimpleNamespace",
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"StringIO",
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"strjoin",
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"Tag",
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"tobytes",
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"tostr",
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"tounicode",
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"unichr",
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"unicode",
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"UnicodeIO",
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"xrange",
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"zip",
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]
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class Py23Error(NotImplementedError):
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pass
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RecursionError = RecursionError
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StringIO = UnicodeIO
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basestring = str
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isclose = _math.isclose
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isfinite = _math.isfinite
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open = open
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range = range
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round = round3 = round
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unichr = chr
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unicode = str
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zip = zip
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tounicode = tostr
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def xrange(*args, **kwargs):
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raise Py23Error("'xrange' is not defined. Use 'range' instead.")
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def round2(number, ndigits=None):
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"""
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Implementation of Python 2 built-in round() function.
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Rounds a number to a given precision in decimal digits (default
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0 digits). The result is a floating point number. Values are rounded
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to the closest multiple of 10 to the power minus ndigits; if two
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multiples are equally close, rounding is done away from 0.
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ndigits may be negative.
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See Python 2 documentation:
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https://docs.python.org/2/library/functions.html?highlight=round#round
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"""
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if ndigits is None:
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ndigits = 0
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if ndigits < 0:
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exponent = 10 ** (-ndigits)
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quotient, remainder = divmod(number, exponent)
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if remainder >= exponent // 2 and number >= 0:
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quotient += 1
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return float(quotient * exponent)
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else:
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exponent = _decimal.Decimal("10") ** (-ndigits)
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d = _decimal.Decimal.from_float(number).quantize(
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exponent, rounding=_decimal.ROUND_HALF_UP
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)
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return float(d)
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